| Line | Branch | Exec | Source |
|---|---|---|---|
| 1 | /* | ||
| 2 | ** EPITECH PROJECT, 2023 | ||
| 3 | ** my_find_nbr | ||
| 4 | ** File description: | ||
| 5 | ** Find the first number (number) found in a string | ||
| 6 | */ | ||
| 7 | /** | ||
| 8 | * @file my_find_nbr.c | ||
| 9 | * @brief The file containing the my_find_nbr function | ||
| 10 | * @author Nicolas TORO | ||
| 11 | */ | ||
| 12 | |||
| 13 | #include "my.h" | ||
| 14 | |||
| 15 | 5 | int my_find_nbr(char const *number) | |
| 16 | { | ||
| 17 | 5 | int nb = -1; | |
| 18 | 5 | int start = -1; | |
| 19 | |||
| 20 |
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5 | if (number[0] == '\0') |
| 21 | 1 | return -1; | |
| 22 |
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7 | for (int index = 0; number[index] != '\0'; index++) { |
| 23 |
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5 | if (number[index] >= '0' && start == -1 && number[index] <= '9') |
| 24 | 2 | nb = 0; | |
| 25 |
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5 | if (start == -1 && number[index] >= '1' && number[index] <= '9') |
| 26 | 1 | start = index; | |
| 27 |
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5 | if (number[index] < '0' || number[index] > '9') |
| 28 | 2 | return nb; | |
| 29 | 3 | nb = nb * 10 + (number[index] - 48); | |
| 30 | } | ||
| 31 | 2 | return nb; | |
| 32 | } | ||
| 33 |